What are the solutions to the equation 2x^2+14=-20x ?

The solutions to the equation 2x^2+14=-20x are x=-5+3sqrt(2),x=-5-3sqrt(2)

Find the zeros of 2x^2+14=-20x

The zeros of 2x^2+14=-20x are x=-5+3sqrt(2),x=-5-3sqrt(2)

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2 x^{2} + 14 = - 20 x

x = - 5 + 32, x = - 5 - 32

Decimal Notation

x = - 0.75735 \dots, x = - 9.24264 \dots

Solution steps

2 x^{2} + 14 = - 20 x

Move

20 x

to the left side

2 x^{2} + 14 + 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 20 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 \cdot 14 = 122

x_{1, 2} = \frac{- 20 \pm 12 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 12 2}{2 \cdot 2}, x_{2} = \frac{- 20 - 12 2}{2 \cdot 2}

x = \frac{- 20 + 12 2}{2 \cdot 2} : - 5 + 32

x = \frac{- 20 - 12 2}{2 \cdot 2} : - 5 - 32

The solutions to the quadratic equation are:

x = - 5 + 32, x = - 5 - 32

x^{3} + 216

f = f

∣ w ∣ \geq 4

- 2 x^{2} + 8 x + 1 = 0

x^{2} - 11 x = - 28

What are the solutions to the equation 2x^2+14=-20x ?
The solutions to the equation 2x^2+14=-20x are x=-5+3sqrt(2),x=-5-3sqrt(2)
Find the zeros of 2x^2+14=-20x
The zeros of 2x^2+14=-20x are x=-5+3sqrt(2),x=-5-3sqrt(2)