What are the solutions to the equation 3t^2=27 ?

The solutions to the equation 3t^2=27 are t=3,t=-3

Find the zeros of 3t^2=27

The zeros of 3t^2=27 are t=3,t=-3

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3 t^{2} = 27

t = 3, t = - 3

Solution steps

3 t^{2} = 27

Divide both sides by

3

t^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 9, t = - 9

9 = 3

- 9 = - 3

t = 3, t = - 3

- 3 n - 7 + (- 6 n) + 1

8 v^{2} + v = - 9

8 + ∣ 4 x + 1 ∣ = 8

2 y + 42 + 2 y = 6

7 x - 12 = 23

What are the solutions to the equation 3t^2=27 ?
The solutions to the equation 3t^2=27 are t=3,t=-3
Find the zeros of 3t^2=27
The zeros of 3t^2=27 are t=3,t=-3