What is log_{2}(6.4)+log_{2}(10)-log_{2}(2) ?

The solution to log_{2}(6.4)+log_{2}(10)-log_{2}(2) is 5

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simplify log_{2}(6.4)+log_{2}(10)-log_{2}(2)

simplify

lo g_{2} (6.4) + lo g_{2} (10) - lo g_{2} (2)

5

Solution steps

lo g_{2} (6.4) + lo g_{2} (10) - lo g_{2} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (6.4) + lo g_{2} (10) = lo g_{2} (6.4 \cdot 10)

= lo g_{2} (6.4 \cdot 10) - lo g_{2} (2)

lo g_{2} (6.4 \cdot 10) = 6

lo g_{2} (2) = 1

= 6 - 1

Subtract the numbers:

6 - 1 = 5

= 5

- 29 \leq 9 x - 2 < 16

4^{2} + 3^{2}

∣ x + 7 ∣ \leq 3

q^{9}

\frac{1}{2} e^{- \frac{8}{2}} \cdot 100

What is log_{2}(6.4)+log_{2}(10)-log_{2}(2) ?
The solution to log_{2}(6.4)+log_{2}(10)-log_{2}(2) is 5