What is the answer to x-(3x-2)/(10)=(16x-17)/(20)+1 ?

The answer to x-(3x-2)/(10)=(16x-17)/(20)+1 is x= 1/2

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x-(3x-2)/(10)=(16x-17)/(20)+1

x - \frac{3 x - 2}{10} = \frac{16 x - 17}{20} + 1

x = \frac{1}{2}

Solution steps

x - \frac{3 x - 2}{10} = \frac{16 x - 17}{20} + 1

Multiply by LCM

20 x - 2 (3 x - 2) = 16 x + 3

Expand

- 2 (3 x - 2) : - 6 x + 4

20 x - 6 x + 4 = 16 x + 3

Add similar elements:

20 x - 6 x = 14 x

14 x + 4 = 16 x + 3

Move

4

to the right side

14 x = 16 x - 1

Move

16 x

to the left side

- 2 x = - 1

Divide both sides by

- 2

x = \frac{1}{2}

\frac{( 25 ) \cdot 60}{10}

7 - 13

- 5 \leq 3 - 2 x < 8

- 2.7 (920 - 2 t) \cdot (920 - 2 t)^{- \frac{7}{2}}

\frac{1}{\frac{2}{\frac{1}{4}}}

What is the answer to x-(3x-2)/(10)=(16x-17)/(20)+1 ?
The answer to x-(3x-2)/(10)=(16x-17)/(20)+1 is x= 1/2
Solve for x: x-(3x-2)/(10)=(16x-17)/(20)+1
The solution is x= 1/2