What is X^4-12X^2+32<= 0 ?

The solution to X^4-12X^2+32<= 0 is -2sqrt(2)<= X<=-2\lor 2<= X<= 2sqrt(2)

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X^4-12X^2+32<= 0

X^{4} - 12 X^{2} + 32 \leq 0

- 22 \leq X \leq - 2 or 2 \leq X \leq 22

Interval Notation

[- 22, - 2] \cup [2, 22]

Decimal Notation

- 2.82842 \dots \leq X \leq - 2 or 2 \leq X \leq 2.82842 \dots

Solution steps

X^{4} - 12 X^{2} + 32 \leq 0

Factor

X^{4} - 12 X^{2} + 32 : (X + 2) (X - 2) (X + 22) (X - 22)

(X + 2) (X - 2) (X + 22) (X - 22) \leq 0

Identify the intervals

- 22 \leq X \leq - 2 or 2 \leq X \leq 22

5 x^{2} + 3 = 3

\frac{x - 2}{14} = \frac{2}{7}

x = 2 x e^{4} - e^{4} - 2

\frac{9 !}{( 9 - 4 ) ! \cdot 4 !}

- \frac{1}{2} (\frac{1}{2})

What is X^4-12X^2+32<= 0 ?
The solution to X^4-12X^2+32<= 0 is -2sqrt(2)<= X<=-2\lor 2<= X<= 2sqrt(2)