What are the solutions to the equation 4(x-7)^2=12 ?

The solutions to the equation 4(x-7)^2=12 are x=sqrt(3)+7,x=-sqrt(3)+7

Find the zeros of 4(x-7)^2=12

The zeros of 4(x-7)^2=12 are x=sqrt(3)+7,x=-sqrt(3)+7

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4 (x - 7)^{2} = 12

x = 3 + 7, x = - 3 + 7

Decimal Notation

x = 8.73205 \dots, x = 5.26794 \dots

Solution steps

4 (x - 7)^{2} = 12

Divide both sides by

4

(x - 7)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = 3 : x = 3 + 7

Solve

x - 7 = - 3 : x = - 3 + 7

The solutions to the quadratic equation are:

x = 3 + 7, x = - 3 + 7

x^{2} + 2 x - 3 > 0

3 3^{2}

- 7 y + y^{2} - 30

z^{2} - 1

x^{2} < x + 30

What are the solutions to the equation 4(x-7)^2=12 ?
The solutions to the equation 4(x-7)^2=12 are x=sqrt(3)+7,x=-sqrt(3)+7
Find the zeros of 4(x-7)^2=12
The zeros of 4(x-7)^2=12 are x=sqrt(3)+7,x=-sqrt(3)+7