What are the solutions to the equation m^2-14m+49=0 ?

The solutions to the equation m^2-14m+49=0 are m=7

Find the zeros of m^2-14m+49=0

The zeros of m^2-14m+49=0 are m=7

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m^{2} - 14 m + 49 = 0

m = 7

Solution steps

m^{2} - 14 m + 49 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 49 = 0

m_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 1}

m = \frac{- ( - 14 )}{2 \cdot 1}

\frac{- ( - 14 )}{2 \cdot 1} = 7

m = 7

The solution to the quadratic equation is:

m = 7

- \frac{x - 2}{3} - \frac{x - 1}{4} > \frac{x - 3}{2} - 1

- \frac{2}{( \frac{1}{9} ) ^{\frac{3}{2}}}

\frac{b}{1.3} - 5.4 = 1.8

lo g_{3} (5) = x

8 f (g + h) + (g + h)^{2}

What are the solutions to the equation m^2-14m+49=0 ?
The solutions to the equation m^2-14m+49=0 are m=7
Find the zeros of m^2-14m+49=0
The zeros of m^2-14m+49=0 are m=7