What is the answer to (2y+1)(3y+1)=(6y-1)(y+2) ?

The answer to (2y+1)(3y+1)=(6y-1)(y+2) is y= 1/2

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(2y+1)(3y+1)=(6y-1)(y+2)

(2 y + 1) (3 y + 1) = (6 y - 1) (y + 2)

y = \frac{1}{2}

Decimal Notation

y = 0.5

Solution steps

(2 y + 1) (3 y + 1) = (6 y - 1) (y + 2)

Expand

(2 y + 1) (3 y + 1) : 6 y^{2} + 5 y + 1

Expand

(6 y - 1) (y + 2) : 6 y^{2} + 11 y - 2

6 y^{2} + 5 y + 1 = 6 y^{2} + 11 y - 2

Move

1

to the right side

6 y^{2} + 5 y = 6 y^{2} + 11 y - 3

Subtract

6 y^{2} + 11 y

from both sides

6 y^{2} + 5 y - (6 y^{2} + 11 y) = 6 y^{2} + 11 y - 3 - (6 y^{2} + 11 y)

Simplify

- 6 y = - 3

Divide both sides by

- 6

y = \frac{1}{2}

- \frac{10}{4}

2 x^{2} + 8 x - 960

∣ x - 2 ∣ \leq 9

\frac{( - 3 x ^{2} + 1400 x )}{x}

j^{2} - 25

What is the answer to (2y+1)(3y+1)=(6y-1)(y+2) ?
The answer to (2y+1)(3y+1)=(6y-1)(y+2) is y= 1/2
Solve for y: (2y+1)(3y+1)=(6y-1)(y+2)
The solution is y= 1/2