What are the solutions to the equation 7x^2+71x+80=-x-1 ?

The solutions to the equation 7x^2+71x+80=-x-1 are x=-9/7 ,x=-9

Find the zeros of 7x^2+71x+80=-x-1

The zeros of 7x^2+71x+80=-x-1 are x=-9/7 ,x=-9

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7 x^{2} + 71 x + 80 = - x - 1

x = - \frac{9}{7}, x = - 9

Decimal Notation

x = - 1.28571 \dots, x = - 9

Solution steps

7 x^{2} + 71 x + 80 = - x - 1

Move

1

to the left side

7 x^{2} + 71 x + 81 = - x

Move

x

to the left side

7 x^{2} + 72 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 72 \pm 7 2 ^{2} - 4 \cdot 7 \cdot 81}{2 \cdot 7}

7 2^{2} - 4 \cdot 7 \cdot 81 = 54

x_{1, 2} = \frac{- 72 \pm 54}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 72 + 54}{2 \cdot 7}, x_{2} = \frac{- 72 - 54}{2 \cdot 7}

x = \frac{- 72 + 54}{2 \cdot 7} : - \frac{9}{7}

x = \frac{- 72 - 54}{2 \cdot 7} : - 9

The solutions to the quadratic equation are:

x = - \frac{9}{7}, x = - 9

15 \cdot (- 4 i + 2)

\frac{1}{2} (z + 4) - 6 = - 2 z + 8

\frac{9 p ^{2} - 1}{pq - 2 q} \cdot \frac{3 p - 6}{1 - 3 p}

3 x^{2} + 12 x - 135

- 5 \cdot 20

What are the solutions to the equation 7x^2+71x+80=-x-1 ?
The solutions to the equation 7x^2+71x+80=-x-1 are x=-9/7 ,x=-9
Find the zeros of 7x^2+71x+80=-x-1
The zeros of 7x^2+71x+80=-x-1 are x=-9/7 ,x=-9