What are the solutions to the equation (x-2)(3x+5)=0 ?

The solutions to the equation (x-2)(3x+5)=0 are x=2,x=-5/3

Find the zeros of (x-2)(3x+5)=0

The zeros of (x-2)(3x+5)=0 are x=2,x=-5/3

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(x - 2) (3 x + 5) = 0

x = 2, x = - \frac{5}{3}

Decimal Notation

x = 2, x = - 1.66666 \dots

Solution steps

(x - 2) (3 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 3 x + 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

3 x + 5 = 0 : x = - \frac{5}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{3}

(3 2^{\frac{1}{5}})^{3}

4 u v^{2} (2 u - v) + 6 u^{2} v (v - 2 u)

\frac{9 x ^{4} y ^{3}}{3 x ^{10} y ^{7}}

\frac{7 ^{4}}{7}

4 x^{2} + 20 x - 25 = 0

What are the solutions to the equation (x-2)(3x+5)=0 ?
The solutions to the equation (x-2)(3x+5)=0 are x=2,x=-5/3
Find the zeros of (x-2)(3x+5)=0
The zeros of (x-2)(3x+5)=0 are x=2,x=-5/3