What are the solutions to the equation 10x^2+x+6=0 ?

The solutions to the equation 10x^2+x+6=0 are x=-1/20+i(sqrt(239))/(20),x=-1/20-i(sqrt(239))/(20)

Find the zeros of 10x^2+x+6=0

The zeros of 10x^2+x+6=0 are x=-1/20+i(sqrt(239))/(20),x=-1/20-i(sqrt(239))/(20)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10 x^{2} + x + 6 = 0

x = - \frac{1}{20} + i \frac{239}{20}, x = - \frac{1}{20} - i \frac{239}{20}

Solution steps

10 x^{2} + x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 10 \cdot 6}{2 \cdot 10}

Simplify

1^{2} - 4 \cdot 10 \cdot 6 : 239 i

x_{1, 2} = \frac{- 1 \pm 239 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 1 + 239 i}{2 \cdot 10}, x_{2} = \frac{- 1 - 239 i}{2 \cdot 10}

x = \frac{- 1 + 239 i}{2 \cdot 10} : - \frac{1}{20} + i \frac{239}{20}

x = \frac{- 1 - 239 i}{2 \cdot 10} : - \frac{1}{20} - i \frac{239}{20}

The solutions to the quadratic equation are:

x = - \frac{1}{20} + i \frac{239}{20}, x = - \frac{1}{20} - i \frac{239}{20}

x + 2 = 9

(x - 2 - 3 i) (x - 2 + 3 i)

4704

\frac{5 x - 1}{3} > 3

\frac{x + 2}{4} - \frac{x - 1}{5} = 15

What are the solutions to the equation 10x^2+x+6=0 ?
The solutions to the equation 10x^2+x+6=0 are x=-1/20+i(sqrt(239))/(20),x=-1/20-i(sqrt(239))/(20)
Find the zeros of 10x^2+x+6=0
The zeros of 10x^2+x+6=0 are x=-1/20+i(sqrt(239))/(20),x=-1/20-i(sqrt(239))/(20)