What is ((2+3i))/((-4-2i)) ?

The solution to ((2+3i))/((-4-2i)) is -7/10-2/5 i

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simplify ((2+3i))/((-4-2i))

simplify

\frac{( 2 + 3 i )}{( - 4 - 2 i )}

- \frac{7}{10} - \frac{2}{5} i

Solution steps

\frac{2 + 3 i}{- 4 - 2 i}

Multiply by the conjugate

\frac{- 4 + 2 i}{- 4 + 2 i}

= \frac{( 2 + 3 i ) ( - 4 + 2 i )}{( - 4 - 2 i ) ( - 4 + 2 i )}

Simplify

\frac{( 2 + 3 i ) ( - 4 + 2 i )}{( - 4 - 2 i ) ( - 4 + 2 i )} : \frac{- 14 - 8 i}{20}

= \frac{- 14 - 8 i}{20}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{- 14}{20} + \frac{- 8}{20} i

Simplify

\frac{- 14}{20} + \frac{- 8}{20} i : - \frac{7}{10} - \frac{2}{5} i

= - \frac{7}{10} - \frac{2}{5} i

5 x^{2} - 16 x - 16

∣ x + 4 ∣ = 2

4 - 4 i

2 x^{3} + x^{2} - 5 x + 2

a^{x + y} + a^{x} b^{y} - a^{y} b^{x} - b^{x + y}