What are the solutions to the equation 200x-x^2=10x+8625 ?

The solutions to the equation 200x-x^2=10x+8625 are x=75,x=115

Find the zeros of 200x-x^2=10x+8625

The zeros of 200x-x^2=10x+8625 are x=75,x=115

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200 x - x^{2} = 10 x + 8625

x = 75, x = 115

Solution steps

200 x - x^{2} = 10 x + 8625

Move

8625

to the left side

200 x - x^{2} - 8625 = 10 x

Move

10 x

to the left side

- x^{2} + 190 x - 8625 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 190 \pm 19 0 ^{2} - 4 ( - 1 ) ( - 8625 )}{2 ( - 1 )}

19 0^{2} - 4 (- 1) (- 8625) = 40

x_{1, 2} = \frac{- 190 \pm 40}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 190 + 40}{2 ( - 1 )}, x_{2} = \frac{- 190 - 40}{2 ( - 1 )}

x = \frac{- 190 + 40}{2 ( - 1 )} : 75

x = \frac{- 190 - 40}{2 ( - 1 )} : 115

The solutions to the quadratic equation are:

x = 75, x = 115

7 - 3 x = 5 x

6^{2} + 7^{2}

- 4 \leq 3 x - 2 < 6

2 - \frac{1}{4}

\frac{2}{3 x - 1} < \frac{2}{9 x ^{2} - 1}

What are the solutions to the equation 200x-x^2=10x+8625 ?
The solutions to the equation 200x-x^2=10x+8625 are x=75,x=115
Find the zeros of 200x-x^2=10x+8625
The zeros of 200x-x^2=10x+8625 are x=75,x=115