What are the solutions to the equation 3x^2-5x=2 ?

The solutions to the equation 3x^2-5x=2 are x=2,x=-1/3

Find the zeros of 3x^2-5x=2

The zeros of 3x^2-5x=2 are x=2,x=-1/3

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3 x^{2} - 5 x = 2

x = 2, x = - \frac{1}{3}

Solution steps

3 x^{2} - 5 x = 2

Move

2

to the left side

3 x^{2} - 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 2) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 3}

x = \frac{- ( - 5 ) + 7}{2 \cdot 3} : 2

x = \frac{- ( - 5 ) - 7}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{3}

a^{2} + 8 a + 15

6 x^{2} + 39 x - 21

3^{- \frac{1}{2}} \cdot 3 x^{\frac{9}{2}} (3 x)^{- \frac{7}{2}}

- 20 = x - 17

∣ 7 x - 2 ∣ + 1 \geq 9

What are the solutions to the equation 3x^2-5x=2 ?
The solutions to the equation 3x^2-5x=2 are x=2,x=-1/3
Find the zeros of 3x^2-5x=2
The zeros of 3x^2-5x=2 are x=2,x=-1/3