What are the solutions to the equation (m+3)(m-4)=0 ?

The solutions to the equation (m+3)(m-4)=0 are m=-3,m=4

Find the zeros of (m+3)(m-4)=0

The zeros of (m+3)(m-4)=0 are m=-3,m=4

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(m + 3) (m - 4) = 0

m = - 3, m = 4

Solution steps

(m + 3) (m - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m + 3 = 0 or m - 4 = 0

Solve

m + 3 = 0 : m = - 3

Solve

m - 4 = 0 : m = 4

The solutions to the quadratic equation are:

m = - 3, m = 4

x^{2} + 8 x + 4 = 28

\frac{3}{5} + \frac{2}{3}

\frac{( - 2 m ^{4} ) ^{2}}{8 m ^{2}}

a^{\frac{2}{5}} \cdot a^{- 3}

\frac{1}{4} - \frac{1}{36}

What are the solutions to the equation (m+3)(m-4)=0 ?
The solutions to the equation (m+3)(m-4)=0 are m=-3,m=4
Find the zeros of (m+3)(m-4)=0
The zeros of (m+3)(m-4)=0 are m=-3,m=4