What are the solutions to the equation 3+(3-2x)^2=12 ?

The solutions to the equation 3+(3-2x)^2=12 are x=0,x=3

Find the zeros of 3+(3-2x)^2=12

The zeros of 3+(3-2x)^2=12 are x=0,x=3

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3 + (3 - 2 x)^{2} = 12

x = 0, x = 3

Solution steps

3 + (3 - 2 x)^{2} = 12

Move

3

to the right side

(3 - 2 x)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 - 2 x = 9 : x = 0

Solve

3 - 2 x = - 9 : x = 3

The solutions to the quadratic equation are:

x = 0, x = 3

(2 p - 1)^{2} - 3 = (p - 2) (p - 1)

\frac{16 π}{7} - 2 π

8 x + 1 > - 31

c^{3} + c^{2} - c

x^{2} + 0^{2} = 49

What are the solutions to the equation 3+(3-2x)^2=12 ?
The solutions to the equation 3+(3-2x)^2=12 are x=0,x=3
Find the zeros of 3+(3-2x)^2=12
The zeros of 3+(3-2x)^2=12 are x=0,x=3