What are the solutions to the equation 4x^2+24x+32=0 ?

The solutions to the equation 4x^2+24x+32=0 are x=-2,x=-4

Find the zeros of 4x^2+24x+32=0

The zeros of 4x^2+24x+32=0 are x=-2,x=-4

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4 x^{2} + 24 x + 32 = 0

x = - 2, x = - 4

Solution steps

4 x^{2} + 24 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 32}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 \cdot 32 = 8

x_{1, 2} = \frac{- 24 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 24 + 8}{2 \cdot 4}, x_{2} = \frac{- 24 - 8}{2 \cdot 4}

x = \frac{- 24 + 8}{2 \cdot 4} : - 2

x = \frac{- 24 - 8}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

x = - 2, x = - 4

x^{2} - 2 x = - 10

12 - \frac{5 x}{2} \geq \frac{x}{4} + 1

49 a^{2} b^{2} - 14 ab + 1

- t^{5} + t^{3}

\frac{0}{7}

What are the solutions to the equation 4x^2+24x+32=0 ?
The solutions to the equation 4x^2+24x+32=0 are x=-2,x=-4
Find the zeros of 4x^2+24x+32=0
The zeros of 4x^2+24x+32=0 are x=-2,x=-4