What are the solutions to the equation z^2+6z=-8 ?

The solutions to the equation z^2+6z=-8 are z=-2,z=-4

Find the zeros of z^2+6z=-8

The zeros of z^2+6z=-8 are z=-2,z=-4

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z^{2} + 6 z = - 8

z = - 2, z = - 4

Solution steps

z^{2} + 6 z = - 8

Move

8

to the left side

z^{2} + 6 z + 8 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

z_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 6 + 2}{2 \cdot 1}, z_{2} = \frac{- 6 - 2}{2 \cdot 1}

z = \frac{- 6 + 2}{2 \cdot 1} : - 2

z = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

z = - 2, z = - 4

112 = 112 + 96 t - 16 t^{2}

12 x^{3} - 9 x^{2}

- 5 n - 6 n \leq 8 - 8 n - n

(x - 4)^{2} = 27

lo g_{2} (\frac{1}{16})

What are the solutions to the equation z^2+6z=-8 ?
The solutions to the equation z^2+6z=-8 are z=-2,z=-4
Find the zeros of z^2+6z=-8
The zeros of z^2+6z=-8 are z=-2,z=-4