What is the answer to k+4-5(k+2)=3k-2 ?

The answer to k+4-5(k+2)=3k-2 is k=-4/7

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k+4-5(k+2)=3k-2

k + 4 - 5 (k + 2) = 3 k - 2

k = - \frac{4}{7}

Decimal Notation

k = - 0.57142 \dots

Solution steps

k + 4 - 5 (k + 2) = 3 k - 2

Expand

k + 4 - 5 (k + 2) : - 4 k - 6

- 4 k - 6 = 3 k - 2

Move

6

to the right side

- 4 k = 3 k + 4

Move

3 k

to the left side

- 7 k = 4

Divide both sides by

- 7

k = - \frac{4}{7}

lo g_{\frac{1}{3}} (1)

x = 3300 (1 + \frac{0.07}{1})^{1 \cdot 1}

3 x^{2} + 9 x + 17 = 0

5 x^{2} + 2 x - 7 = 0

- 281 + - 32 - 3 - 8