What are the solutions to the equation 9a^2+25a+16=a ?

The solutions to the equation 9a^2+25a+16=a are a=-4/3

Find the zeros of 9a^2+25a+16=a

The zeros of 9a^2+25a+16=a are a=-4/3

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9 a^{2} + 25 a + 16 = a

a = - \frac{4}{3}

Decimal Notation

a = - 1.33333 \dots

Solution steps

9 a^{2} + 25 a + 16 = a

Move

a

to the left side

9 a^{2} + 24 a + 16 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 \cdot 16}{2 \cdot 9}

2 4^{2} - 4 \cdot 9 \cdot 16 = 0

a_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 9}

a = \frac{- 24}{2 \cdot 9}

\frac{- 24}{2 \cdot 9} = - \frac{4}{3}

a = - \frac{4}{3}

The solution to the quadratic equation is:

a = - \frac{4}{3}

2 (1 + x^{2}) (2 x^{2} - 2 x x^{2} + 1 + 2)

- 15 \geq 8 k + 9

2 \leq x \leq 7

4 \cdot 32

3 x - 9 x + 6 = 20 - 3 x + 4 x

What are the solutions to the equation 9a^2+25a+16=a ?
The solutions to the equation 9a^2+25a+16=a are a=-4/3
Find the zeros of 9a^2+25a+16=a
The zeros of 9a^2+25a+16=a are a=-4/3