What are the solutions to the equation 4m^2-6m=-360 ?

The solutions to the equation 4m^2-6m=-360 are m= 3/4+i(3sqrt(159))/4 ,m= 3/4-i(3sqrt(159))/4

Find the zeros of 4m^2-6m=-360

The zeros of 4m^2-6m=-360 are m= 3/4+i(3sqrt(159))/4 ,m= 3/4-i(3sqrt(159))/4

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4 m^{2} - 6 m = - 360

m = \frac{3}{4} + i \frac{3 159}{4}, m = \frac{3}{4} - i \frac{3 159}{4}

Solution steps

4 m^{2} - 6 m = - 360

Move

360

to the left side

4 m^{2} - 6 m + 360 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 \cdot 360}{2 \cdot 4}

Simplify

(- 6)^{2} - 4 \cdot 4 \cdot 360 : 6159 i

m_{1, 2} = \frac{- ( - 6 ) \pm 6 159 i}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- ( - 6 ) + 6 159 i}{2 \cdot 4}, m_{2} = \frac{- ( - 6 ) - 6 159 i}{2 \cdot 4}

m = \frac{- ( - 6 ) + 6 159 i}{2 \cdot 4} : \frac{3}{4} + i \frac{3 159}{4}

m = \frac{- ( - 6 ) - 6 159 i}{2 \cdot 4} : \frac{3}{4} - i \frac{3 159}{4}

The solutions to the quadratic equation are:

m = \frac{3}{4} + i \frac{3 159}{4}, m = \frac{3}{4} - i \frac{3 159}{4}

\frac{1 1 ^{9}}{1 1 ^{7}}

\frac{( 2 a ^{3} b ^{4} ) ^{3}}{( 2 a b ^{2} ) ^{5}}

(4 x^{2} z) (y^{3} z^{2})

2 x^{2} - 8 x + 2

n^{2} + 6 n + 5

What are the solutions to the equation 4m^2-6m=-360 ?
The solutions to the equation 4m^2-6m=-360 are m= 3/4+i(3sqrt(159))/4 ,m= 3/4-i(3sqrt(159))/4
Find the zeros of 4m^2-6m=-360
The zeros of 4m^2-6m=-360 are m= 3/4+i(3sqrt(159))/4 ,m= 3/4-i(3sqrt(159))/4