What are the solutions to the equation (3x-1)^2-1=24 ?

The solutions to the equation (3x-1)^2-1=24 are x=2,x=-4/3

Find the zeros of (3x-1)^2-1=24

The zeros of (3x-1)^2-1=24 are x=2,x=-4/3

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(3 x - 1)^{2} - 1 = 24

x = 2, x = - \frac{4}{3}

Decimal Notation

x = 2, x = - 1.33333 \dots

Solution steps

(3 x - 1)^{2} - 1 = 24

Move

1

to the right side

(3 x - 1)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 1 = 25 : x = 2

Solve

3 x - 1 = - 25 : x = - \frac{4}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{4}{3}

6 a^{3} - 3 a^{2} + 8 a - 4

3 m^{4} - 3

x^{2} - 3 x - 7 = 0

\frac{1}{3} - (- \frac{1}{2})

w^{2} - 16 = 0

What are the solutions to the equation (3x-1)^2-1=24 ?
The solutions to the equation (3x-1)^2-1=24 are x=2,x=-4/3
Find the zeros of (3x-1)^2-1=24
The zeros of (3x-1)^2-1=24 are x=2,x=-4/3