What are the solutions to the equation x^2+4x-94=0 ?

The solutions to the equation x^2+4x-94=0 are x=-2+7sqrt(2),x=-2-7sqrt(2)

Find the zeros of x^2+4x-94=0

The zeros of x^2+4x-94=0 are x=-2+7sqrt(2),x=-2-7sqrt(2)

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x^{2} + 4 x - 94 = 0

x = - 2 + 72, x = - 2 - 72

Decimal Notation

x = 7.89949 \dots, x = - 11.89949 \dots

Solution steps

x^{2} + 4 x - 94 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 94 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 94) = 142

x_{1, 2} = \frac{- 4 \pm 14 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 14 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 14 2}{2 \cdot 1}

x = \frac{- 4 + 14 2}{2 \cdot 1} : - 2 + 72

x = \frac{- 4 - 14 2}{2 \cdot 1} : - 2 - 72

The solutions to the quadratic equation are:

x = - 2 + 72, x = - 2 - 72

- 6 x < 18

- 6 x \leq 36

u^{2} - v^{2} + 2 v - 1

5^{- 1} (3^{- 2})

What are the solutions to the equation x^2+4x-94=0 ?
The solutions to the equation x^2+4x-94=0 are x=-2+7sqrt(2),x=-2-7sqrt(2)
Find the zeros of x^2+4x-94=0
The zeros of x^2+4x-94=0 are x=-2+7sqrt(2),x=-2-7sqrt(2)