What are the solutions to the equation x^2-35=-2x ?

The solutions to the equation x^2-35=-2x are x=5,x=-7

Find the zeros of x^2-35=-2x

The zeros of x^2-35=-2x are x=5,x=-7

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x^{2} - 35 = - 2 x

x = 5, x = - 7

Solution steps

x^{2} - 35 = - 2 x

Move

2 x

to the left side

x^{2} - 35 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 35) = 12

x_{1, 2} = \frac{- 2 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 12}{2 \cdot 1}, x_{2} = \frac{- 2 - 12}{2 \cdot 1}

x = \frac{- 2 + 12}{2 \cdot 1} : 5

x = \frac{- 2 - 12}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 5, x = - 7

\frac{5 - x}{2} - \frac{x - 17}{4} \geq \frac{x}{3} - \frac{7 x - 3}{12}

3 (y + 3) + y = 2 (y - 1) + 3

x^{2} + 0 + 1 = 0

3 x y - 6 x + 8 y - 16

6 x - 3 (x - 1) + 22 = 7 x - 11

What are the solutions to the equation x^2-35=-2x ?
The solutions to the equation x^2-35=-2x are x=5,x=-7
Find the zeros of x^2-35=-2x
The zeros of x^2-35=-2x are x=5,x=-7