What are the solutions to the equation 3x^2+14x-5=0 ?

The solutions to the equation 3x^2+14x-5=0 are x= 1/3 ,x=-5

Find the zeros of 3x^2+14x-5=0

The zeros of 3x^2+14x-5=0 are x= 1/3 ,x=-5

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3 x^{2} + 14 x - 5 = 0

x = \frac{1}{3}, x = - 5

Decimal Notation

x = 0.33333 \dots, x = - 5

Solution steps

3 x^{2} + 14 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 (- 5) = 16

x_{1, 2} = \frac{- 14 \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 14 + 16}{2 \cdot 3}, x_{2} = \frac{- 14 - 16}{2 \cdot 3}

x = \frac{- 14 + 16}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 14 - 16}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 5

- x^{2} + 10 x - 21

- 2 x^{2} + 3 x - 1

\frac{3}{8} + \frac{1}{2} - \frac{3}{16}

c^{3} - c^{2} - c + 1

\frac{k}{7} \geq - \frac{1}{7}

What are the solutions to the equation 3x^2+14x-5=0 ?
The solutions to the equation 3x^2+14x-5=0 are x= 1/3 ,x=-5
Find the zeros of 3x^2+14x-5=0
The zeros of 3x^2+14x-5=0 are x= 1/3 ,x=-5