What is 2x^4+5x^3+5x>x^2+3 ?

The solution to 2x^4+5x^3+5x>x^2+3 is x 1/2

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2x^4+5x^3+5x>x^2+3

2 x^{4} + 5 x^{3} + 5 x > x^{2} + 3

x < - 3 or x > \frac{1}{2}

Interval Notation

(- \infty, - 3) \cup (\frac{1}{2}, \infty)

Decimal Notation

x < - 3 or x > 0.5

Solution steps

2 x^{4} + 5 x^{3} + 5 x > x^{2} + 3

Rewrite in standard form

2 x^{4} + 5 x^{3} + 5 x - 3 - x^{2} > 0

Factor

2 x^{4} + 5 x^{3} + 5 x - 3 - x^{2} : (x + 3) (2 x - 1) (x^{2} + 1)

(x + 3) (2 x - 1) (x^{2} + 1) > 0

Identify the intervals

x < - 3 or x > \frac{1}{2}

2 y^{2} - 9 y + 10

\frac{x ( 3 x - 1 )}{2} - \frac{6 x}{3} = \frac{2 x ^{2}}{4} + \frac{10 - 3 x ^{2}}{2}

9 \cdot 16

- 4 x + 5 \leq - 3

39 \geq 3 + 4 n

What is 2x^4+5x^3+5x>x^2+3 ?
The solution to 2x^4+5x^3+5x>x^2+3 is x<-3\lor x> 1/2