What are the solutions to the equation z^2+2z-35=0 ?

The solutions to the equation z^2+2z-35=0 are z=5,z=-7

Find the zeros of z^2+2z-35=0

The zeros of z^2+2z-35=0 are z=5,z=-7

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z^{2} + 2 z - 35 = 0

z = 5, z = - 7

Solution steps

z^{2} + 2 z - 35 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 35) = 12

z_{1, 2} = \frac{- 2 \pm 12}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 2 + 12}{2 \cdot 1}, z_{2} = \frac{- 2 - 12}{2 \cdot 1}

z = \frac{- 2 + 12}{2 \cdot 1} : 5

z = \frac{- 2 - 12}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

z = 5, z = - 7

\frac{r + 2}{8} = \frac{3}{2}

15 x^{2} + 31 x + 2

\frac{5.00 1 ^{2} - 5 ( 5.001 )}{5.00 1 ^{2} - 25}

∣ x - 4 ∣ \leq 4

5 x - 2 = 3

What are the solutions to the equation z^2+2z-35=0 ?
The solutions to the equation z^2+2z-35=0 are z=5,z=-7
Find the zeros of z^2+2z-35=0
The zeros of z^2+2z-35=0 are z=5,z=-7