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Popular >

|4(x-1)+2|<= 22

Solution

∣ 4 (x - 1) + 2 ∣ \leq 22

Solution

- 5 \leq x \leq 6

+1

Interval Notation

[- 5, 6]

Solution steps

∣ 4 (x - 1) + 2 ∣ \leq 22

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 22 \leq 4 (x - 1) + 2 \leq 22

4 (x - 1) + 2 \geq - 22 and 4 (x - 1) + 2 \leq 22

x \geq - 5 and x \leq 6

Merge Overlapping Intervals

- 5 \leq x \leq 6

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-2(-x+1)+3x+3=26

- 2 (- x + 1) + 3 x + 3 = 26

(15-y)^2+y^2=125

(15 - y)^{2} + y^{2} = 125

Frequently Asked Questions (FAQ)

What is |4(x-1)+2|<= 22 ?
The solution to |4(x-1)+2|<= 22 is -5<= x<= 6