What are the solutions to the equation u^2-2u=15 ?

The solutions to the equation u^2-2u=15 are u=5,u=-3

Find the zeros of u^2-2u=15

The zeros of u^2-2u=15 are u=5,u=-3

Popular >

u^{2} - 2 u = 15

u = 5, u = - 3

Solution steps

u^{2} - 2 u = 15

Move

15

to the left side

u^{2} - 2 u - 15 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

u_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, u_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

u = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

u = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

u = 5, u = - 3

4 \cdot \frac{2}{5}

f (n) = \frac{n ^{4} - 11 n ^{2} + 30}{n ^{4} - 7 n ^{2} + 10}

1.4 z + 2.2 > 2.6 z - 0.2

∣ 3 x + 6 ∣ - 9 > 3

\frac{1}{6} + \frac{1}{3}

What are the solutions to the equation u^2-2u=15 ?
The solutions to the equation u^2-2u=15 are u=5,u=-3
Find the zeros of u^2-2u=15
The zeros of u^2-2u=15 are u=5,u=-3