What are the solutions to the equation d^2+20d+11=200 ?

The solutions to the equation d^2+20d+11=200 are d=7,d=-27

Find the zeros of d^2+20d+11=200

The zeros of d^2+20d+11=200 are d=7,d=-27

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d^{2} + 20 d + 11 = 200

d = 7, d = - 27

Solution steps

d^{2} + 20 d + 11 = 200

Move

200

to the left side

d^{2} + 20 d - 189 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 189 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 189) = 34

d_{1, 2} = \frac{- 20 \pm 34}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- 20 + 34}{2 \cdot 1}, d_{2} = \frac{- 20 - 34}{2 \cdot 1}

d = \frac{- 20 + 34}{2 \cdot 1} : 7

d = \frac{- 20 - 34}{2 \cdot 1} : - 27

The solutions to the quadratic equation are:

d = 7, d = - 27

n^{2} + 8 n + 15 = 0

\frac{x + 3}{4} < \frac{2 x - 4}{3}

lo g_{2} (- 3)

(\frac{1}{40}) (\frac{2 π}{1}) (60)

What are the solutions to the equation d^2+20d+11=200 ?
The solutions to the equation d^2+20d+11=200 are d=7,d=-27
Find the zeros of d^2+20d+11=200
The zeros of d^2+20d+11=200 are d=7,d=-27