What are the solutions to the equation 4x^2-7x+3=0 ?

The solutions to the equation 4x^2-7x+3=0 are x=1,x= 3/4

Find the zeros of 4x^2-7x+3=0

The zeros of 4x^2-7x+3=0 are x=1,x= 3/4

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4 x^{2} - 7 x + 3 = 0

x = 1, x = \frac{3}{4}

Decimal Notation

x = 1, x = 0.75

Solution steps

4 x^{2} - 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 \cdot 3 = 1

x_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 4}, x_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 4}

x = \frac{- ( - 7 ) + 1}{2 \cdot 4} : 1

x = \frac{- ( - 7 ) - 1}{2 \cdot 4} : \frac{3}{4}

The solutions to the quadratic equation are:

x = 1, x = \frac{3}{4}

1 0^{- 6}

- 4.905 x^{2} + 10 x + 20 = 0

3 a x - a y - 3 b x + b y

\frac{7}{4} - \frac{2}{5}

What are the solutions to the equation 4x^2-7x+3=0 ?
The solutions to the equation 4x^2-7x+3=0 are x=1,x= 3/4
Find the zeros of 4x^2-7x+3=0
The zeros of 4x^2-7x+3=0 are x=1,x= 3/4