What are the solutions to the equation 0=x^2-5x+6 ?

The solutions to the equation 0=x^2-5x+6 are x=3,x=2

Find the zeros of 0=x^2-5x+6

The zeros of 0=x^2-5x+6 are x=3,x=2

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0 = x^{2} - 5 x + 6

x = 3, x = 2

Solution steps

0 = x^{2} - 5 x + 6

Switch sides

x^{2} - 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

x = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

x = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 3, x = 2

lo g_{10} (5)

lo g_{0.5} (1)

\frac{2}{- 10}

∣ 4 x - 2 ∣ + 1 = 15

1 - \frac{1}{1}

What are the solutions to the equation 0=x^2-5x+6 ?
The solutions to the equation 0=x^2-5x+6 are x=3,x=2
Find the zeros of 0=x^2-5x+6
The zeros of 0=x^2-5x+6 are x=3,x=2