What are the solutions to the equation 8n^2-10=10n ?

The solutions to the equation 8n^2-10=10n are n=(5+sqrt(105))/8 ,n=(5-sqrt(105))/8

Find the zeros of 8n^2-10=10n

The zeros of 8n^2-10=10n are n=(5+sqrt(105))/8 ,n=(5-sqrt(105))/8

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8 n^{2} - 10 = 10 n

n = \frac{5 + 105}{8}, n = \frac{5 - 105}{8}

Decimal Notation

n = 1.90586 \dots, n = - 0.65586 \dots

Solution steps

8 n^{2} - 10 = 10 n

Move

10 n

to the left side

8 n^{2} - 10 - 10 n = 0

Write in the standard form

a x^{2} + b x + c = 0

8 n^{2} - 10 n - 10 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 8 ( - 10 )}{2 \cdot 8}

(- 10)^{2} - 4 \cdot 8 (- 10) = 2105

n_{1, 2} = \frac{- ( - 10 ) \pm 2 105}{2 \cdot 8}

Separate the solutions

n_{1} = \frac{- ( - 10 ) + 2 105}{2 \cdot 8}, n_{2} = \frac{- ( - 10 ) - 2 105}{2 \cdot 8}

n = \frac{- ( - 10 ) + 2 105}{2 \cdot 8} : \frac{5 + 105}{8}

n = \frac{- ( - 10 ) - 2 105}{2 \cdot 8} : \frac{5 - 105}{8}

The solutions to the quadratic equation are:

n = \frac{5 + 105}{8}, n = \frac{5 - 105}{8}

x^{2} - 14 x + 46 = 0

- 2 x^{2} - x + 2 = 0

e^{1} = m

x^{2} + 2 x - 35 < 0

(x^{\frac{1}{4}})^{2}

What are the solutions to the equation 8n^2-10=10n ?
The solutions to the equation 8n^2-10=10n are n=(5+sqrt(105))/8 ,n=(5-sqrt(105))/8
Find the zeros of 8n^2-10=10n
The zeros of 8n^2-10=10n are n=(5+sqrt(105))/8 ,n=(5-sqrt(105))/8