What are the solutions to the equation (3x-10)^2-6=1 ?

The solutions to the equation (3x-10)^2-6=1 are x=(sqrt(7)+10)/3 ,x=(-sqrt(7)+10)/3

Find the zeros of (3x-10)^2-6=1

The zeros of (3x-10)^2-6=1 are x=(sqrt(7)+10)/3 ,x=(-sqrt(7)+10)/3

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(3 x - 10)^{2} - 6 = 1

x = \frac{7 + 10}{3}, x = \frac{- 7 + 10}{3}

Decimal Notation

x = 4.21525 \dots, x = 2.45141 \dots

Solution steps

(3 x - 10)^{2} - 6 = 1

Move

6

to the right side

(3 x - 10)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 10 = 7 : x = \frac{7 + 10}{3}

Solve

3 x - 10 = - 7 : x = \frac{- 7 + 10}{3}

The solutions to the quadratic equation are:

x = \frac{7 + 10}{3}, x = \frac{- 7 + 10}{3}

2 x + 2 = x + 1

- 16 t^{2} + 5 t + 5 = 0

- \frac{1}{3} h \geq 8

16 \frac{- 1}{2}

21 m^{5} n - 7 m^{4} n^{2} + 7 m^{3} n^{3} - 7 m^{2} n

What are the solutions to the equation (3x-10)^2-6=1 ?
The solutions to the equation (3x-10)^2-6=1 are x=(sqrt(7)+10)/3 ,x=(-sqrt(7)+10)/3
Find the zeros of (3x-10)^2-6=1
The zeros of (3x-10)^2-6=1 are x=(sqrt(7)+10)/3 ,x=(-sqrt(7)+10)/3