What are the solutions to the equation r^2+25=-12r ?

The solutions to the equation r^2+25=-12r are r=-6+sqrt(11),r=-6-sqrt(11)

Find the zeros of r^2+25=-12r

The zeros of r^2+25=-12r are r=-6+sqrt(11),r=-6-sqrt(11)

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r^{2} + 25 = - 12 r

r = - 6 + 11, r = - 6 - 11

Decimal Notation

r = - 2.68337 \dots, r = - 9.31662 \dots

Solution steps

r^{2} + 25 = - 12 r

Move

12 r

to the left side

r^{2} + 25 + 12 r = 0

Write in the standard form

a x^{2} + b x + c = 0

r^{2} + 12 r + 25 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 25 = 211

r_{1, 2} = \frac{- 12 \pm 2 11}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 12 + 2 11}{2 \cdot 1}, r_{2} = \frac{- 12 - 2 11}{2 \cdot 1}

r = \frac{- 12 + 2 11}{2 \cdot 1} : - 6 + 11

r = \frac{- 12 - 2 11}{2 \cdot 1} : - 6 - 11

The solutions to the quadratic equation are:

r = - 6 + 11, r = - 6 - 11

\frac{2}{3} = 2 x + 1

34 = 10 x + 14

8 + 2 x \leq 5

x^{2}

x^{4} - 4 x^{3} + 8 x^{2} - 16 x + 16

What are the solutions to the equation r^2+25=-12r ?
The solutions to the equation r^2+25=-12r are r=-6+sqrt(11),r=-6-sqrt(11)
Find the zeros of r^2+25=-12r
The zeros of r^2+25=-12r are r=-6+sqrt(11),r=-6-sqrt(11)