What are the solutions to the equation 1=(x-2)^2 ?

The solutions to the equation 1=(x-2)^2 are x=3,x=1

Find the zeros of 1=(x-2)^2

The zeros of 1=(x-2)^2 are x=3,x=1

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1 = (x - 2)^{2}

x = 3, x = 1

Solution steps

1 = (x - 2)^{2}

Switch sides

(x - 2)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 1 : x = 3

Solve

x - 2 = - 1 : x = 1

The solutions to the quadratic equation are:

x = 3, x = 1

\frac{1.9864 \cdot 1 0 ^{- 25}}{4 \cdot 1 0 ^{- 7}}

\frac{m}{3} + 4 = 21

2 x^{2} - 4 x + 2 y^{2} + 6 y - 10

\frac{3}{10} + \frac{4}{15}

- 6 x^{2} - x + 1 = 0

What are the solutions to the equation 1=(x-2)^2 ?
The solutions to the equation 1=(x-2)^2 are x=3,x=1
Find the zeros of 1=(x-2)^2
The zeros of 1=(x-2)^2 are x=3,x=1