What is (1+i)/(2-i)+(-3-2i)/(1+3i) ?

The solution to (1+i)/(2-i)+(-3-2i)/(1+3i) is -7/10+13/10 i

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simplify (1+i)/(2-i)+(-3-2i)/(1+3i)

simplify

\frac{1 + i}{2 - i} + \frac{- 3 - 2 i}{1 + 3 i}

- \frac{7}{10} + \frac{13}{10} i

Solution steps

\frac{1 + i}{2 - i} + \frac{- 3 - 2 i}{1 + 3 i}

\frac{1 + i}{2 - i} = \frac{1 + 3 i}{5}

\frac{- 3 - 2 i}{1 + 3 i} = \frac{- 9 + 7 i}{10}

= \frac{1 + 3 i}{5} + \frac{- 9 + 7 i}{10}

Join

\frac{1 + 3 i}{5} + \frac{- 9 + 7 i}{10} : \frac{13 i - 7}{10}

= \frac{13 i - 7}{10}

Rewrite in standard complex form:

- \frac{7}{10} + \frac{13}{10} i

= - \frac{7}{10} + \frac{13}{10} i

∣ 2 x - 2 ∣ = ∣ - 6 ∣

3 - 3 i

x^{3} - 27 x + 54

\frac{p + q}{p - q} - 2

11 b^{2} (3 b - y) - (6 y - 3 b^{2}) (y - 3 b)

What is (1+i)/(2-i)+(-3-2i)/(1+3i) ?
The solution to (1+i)/(2-i)+(-3-2i)/(1+3i) is -7/10+13/10 i