What are the solutions to the equation t^2-23t=0 ?

The solutions to the equation t^2-23t=0 are t=23,t=0

Find the zeros of t^2-23t=0

The zeros of t^2-23t=0 are t=23,t=0

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t^{2} - 23 t = 0

t = 23, t = 0

Solution steps

t^{2} - 23 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 23)^{2} - 4 \cdot 1 \cdot 0 = 23

t_{1, 2} = \frac{- ( - 23 ) \pm 23}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 23 ) + 23}{2 \cdot 1}, t_{2} = \frac{- ( - 23 ) - 23}{2 \cdot 1}

t = \frac{- ( - 23 ) + 23}{2 \cdot 1} : 23

t = \frac{- ( - 23 ) - 23}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 23, t = 0

8 m^{2} + 30 m + 7

\frac{6}{8}

- 6 < 5 x + 4 \leq 11

- \frac{3}{4} + \frac{1}{2}

∣ x + 5 ∣ = 2 x - 4

What are the solutions to the equation t^2-23t=0 ?
The solutions to the equation t^2-23t=0 are t=23,t=0
Find the zeros of t^2-23t=0
The zeros of t^2-23t=0 are t=23,t=0