What is ((-5x^3y+2^2y^2-6xy^3))/((4^2y^3)) ?

The solution to ((-5x^3y+2^2y^2-6xy^3))/((4^2y^3)) is -(5x^3-4y+6xy^2)/(16y^2)

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simplify ((-5x^3y+2^2y^2-6xy^3))/((4^2y^3))

simplify

\frac{( - 5 x ^{3} y + 2 ^{2} y ^{2} - 6 x y ^{3} )}{( 4 ^{2} y ^{3} )}

- \frac{5 x ^{3} - 4 y + 6 x y ^{2}}{16 y ^{2}}

Solution steps

\frac{- 5 x ^{3} y + 2 ^{2} y ^{2} - 6 x y ^{3}}{4 ^{2} y ^{3}}

Factor out

- 1 : - (5 x^{3} y - 4 y^{2} + 6 x y^{3})

= \frac{- ( 5 x ^{3} y - 4 y ^{2} + 6 x y ^{3} )}{4 ^{2} y ^{3}}

Factor

5 x^{3} y - 4 y^{2} + 6 x y^{3} : y (5 x^{3} - 4 y + 6 x y^{2})

= \frac{- y ( 5 x ^{3} - 4 y + 6 x y ^{2} )}{4 ^{2} y ^{3}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

y^{3} = y y^{2}

= \frac{- y ( 5 x ^{3} - 4 y + 6 x y ^{2} )}{4 ^{2} y y ^{2}}

Cancel the common factor:

y

= \frac{- ( 5 x ^{3} - 4 y + 6 x y ^{2} )}{4 ^{2} y ^{2}}

Simplify

\frac{- ( 5 x ^{3} - 4 y + 6 x y ^{2} )}{4 ^{2} y ^{2}} : - \frac{5 x ^{3} - 4 y + 6 x y ^{2}}{16 y ^{2}}

= - \frac{5 x ^{3} - 4 y + 6 x y ^{2}}{16 y ^{2}}

2 + 7 x \leq 3 x - 10

∣ 2 y + 5 ∣ < 1

\frac{4}{3}

∣ 2 x + 9 ∣ < 25

\frac{7}{6} - (- \frac{1}{9})

What is ((-5x^3y+2^2y^2-6xy^3))/((4^2y^3)) ?
The solution to ((-5x^3y+2^2y^2-6xy^3))/((4^2y^3)) is -(5x^3-4y+6xy^2)/(16y^2)