What are the solutions to the equation 2x^2+5x+12=0 ?

The solutions to the equation 2x^2+5x+12=0 are x=-5/4+i(sqrt(71))/4 ,x=-5/4-i(sqrt(71))/4

Find the zeros of 2x^2+5x+12=0

The zeros of 2x^2+5x+12=0 are x=-5/4+i(sqrt(71))/4 ,x=-5/4-i(sqrt(71))/4

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2 x^{2} + 5 x + 12 = 0

x = - \frac{5}{4} + i \frac{71}{4}, x = - \frac{5}{4} - i \frac{71}{4}

Solution steps

2 x^{2} + 5 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

Simplify

5^{2} - 4 \cdot 2 \cdot 12 : 71 i

x_{1, 2} = \frac{- 5 \pm 71 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 71 i}{2 \cdot 2}, x_{2} = \frac{- 5 - 71 i}{2 \cdot 2}

x = \frac{- 5 + 71 i}{2 \cdot 2} : - \frac{5}{4} + i \frac{71}{4}

x = \frac{- 5 - 71 i}{2 \cdot 2} : - \frac{5}{4} - i \frac{71}{4}

The solutions to the quadratic equation are:

x = - \frac{5}{4} + i \frac{71}{4}, x = - \frac{5}{4} - i \frac{71}{4}

8 x^{2} - 9 x + 1

lo g_{2} (0.5) = x

\frac{3}{2} - \frac{3}{4}

- 318 + 38 - 24

2 (0)

What are the solutions to the equation 2x^2+5x+12=0 ?
The solutions to the equation 2x^2+5x+12=0 are x=-5/4+i(sqrt(71))/4 ,x=-5/4-i(sqrt(71))/4
Find the zeros of 2x^2+5x+12=0
The zeros of 2x^2+5x+12=0 are x=-5/4+i(sqrt(71))/4 ,x=-5/4-i(sqrt(71))/4