7t-t^2<0

Solution

7 t - t^{2} < 0

t < 0 or t > 7

Interval Notation

(- \infty, 0) \cup (7, \infty)

Solution steps

7 t - t^{2} < 0

Factor

7 t - t^{2} : - t (t - 7)

- t (t - 7) < 0

Multiply both sides by

- 1

(reverse the inequality)

(- t (t - 7)) (- 1) > 0 \cdot (- 1)

Simplify

t (t - 7) > 0

Identify the intervals

t < 0 or t > 7

∣ x + 4 ∣ + 9 = 8

3 m - 2 (m + 3) = m

2 n^{2} - 6 n = 8

u^{2} = 11 u

x^{2} - x - 1 > 0