What is (4c^{-3}d^{-3})(-7c^{-3}d) ?

The solution to (4c^{-3}d^{-3})(-7c^{-3}d) is -(28)/(c^6d^2)

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simplify (4c^{-3}d^{-3})(-7c^{-3}d)

simplify

(4 c^{- 3} d^{- 3}) (- 7 c^{- 3} d)

- \frac{28}{c ^{6} d ^{2}}

Solution steps

(4 c^{- 3} d^{- 3}) (- 7 c^{- 3} d)

Apply rule:

a (- b) = - ab

(4 c^{- 3} d^{- 3}) (- 7 c^{- 3} d) = - 4 c^{- 3} d^{- 3} \cdot 7 c^{- 3} d

= - 4 c^{- 3} d^{- 3} \cdot 7 c^{- 3} d

Multiply the numbers:

- 4 \cdot 7 = - 28

= - 28 c^{- 3} d^{- 3} c^{- 3} d

Simplify

c^{- 3} c^{- 3} : \frac{1}{c ^{6}}

= - 28 \cdot \frac{1}{c ^{6}} d^{- 3} d

Simplify

d^{- 3} d : \frac{1}{d ^{2}}

= - 28 \cdot \frac{1}{c ^{6}} \cdot \frac{1}{d ^{2}}

Simplify

- 28 \cdot \frac{1}{c ^{6}} \cdot \frac{1}{d ^{2}} : - \frac{28}{c ^{6} d ^{2}}

= - \frac{28}{c ^{6} d ^{2}}

\frac{11}{12} - \frac{3}{8}

\frac{a ^{3} b ^{3} c ^{5}}{a b ^{6} c ^{2}}

x^{2} + 6 x + 9 = 25

5 (x - 1) + x - 8 = - x

3 x + 4 \leq 7 or \frac{5 x + 4}{2} > 7

What is (4c^{-3}d^{-3})(-7c^{-3}d) ?
The solution to (4c^{-3}d^{-3})(-7c^{-3}d) is -(28)/(c^6d^2)