What are the solutions to the equation 2x^2-22=-4x ?

The solutions to the equation 2x^2-22=-4x are x=-1+2sqrt(3),x=-1-2sqrt(3)

Find the zeros of 2x^2-22=-4x

The zeros of 2x^2-22=-4x are x=-1+2sqrt(3),x=-1-2sqrt(3)

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2 x^{2} - 22 = - 4 x

x = - 1 + 23, x = - 1 - 23

Decimal Notation

x = 2.46410 \dots, x = - 4.46410 \dots

Solution steps

2 x^{2} - 22 = - 4 x

Move

4 x

to the left side

2 x^{2} - 22 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 4 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 22 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 22) = 83

x_{1, 2} = \frac{- 4 \pm 8 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 8 3}{2 \cdot 2}, x_{2} = \frac{- 4 - 8 3}{2 \cdot 2}

x = \frac{- 4 + 8 3}{2 \cdot 2} : - 1 + 23

x = \frac{- 4 - 8 3}{2 \cdot 2} : - 1 - 23

The solutions to the quadratic equation are:

x = - 1 + 23, x = - 1 - 23

\frac{x}{2} + 1 = \frac{x}{3}

y, x^{4} + y^{2} - x y = 81

8^{2} + 1 2^{2} = c^{2}

∣ 5 x + 3 ∣ = 16

- 1 < 2 - x < 3

What are the solutions to the equation 2x^2-22=-4x ?
The solutions to the equation 2x^2-22=-4x are x=-1+2sqrt(3),x=-1-2sqrt(3)
Find the zeros of 2x^2-22=-4x
The zeros of 2x^2-22=-4x are x=-1+2sqrt(3),x=-1-2sqrt(3)