What are the solutions to the equation (x^2+2x)+x+2=0 ?

The solutions to the equation (x^2+2x)+x+2=0 are x=-1,x=-2

Find the zeros of (x^2+2x)+x+2=0

The zeros of (x^2+2x)+x+2=0 are x=-1,x=-2

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(x^{2} + 2 x) + x + 2 = 0

x = - 1, x = - 2

Solution steps

(x^{2} + 2 x) + x + 2 = 0

Refine

x^{2} + 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 1}{2 \cdot 1}, x_{2} = \frac{- 3 - 1}{2 \cdot 1}

x = \frac{- 3 + 1}{2 \cdot 1} : - 1

x = \frac{- 3 - 1}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = - 1, x = - 2

16 - 25 x^{2}

6 x^{2} = - 5 x + 6

\frac{1}{2} 40

1 3^{0}

(1 - 3 i)^{\frac{1}{3}}

What are the solutions to the equation (x^2+2x)+x+2=0 ?
The solutions to the equation (x^2+2x)+x+2=0 are x=-1,x=-2
Find the zeros of (x^2+2x)+x+2=0
The zeros of (x^2+2x)+x+2=0 are x=-1,x=-2