What are the solutions to the equation (7x-2)^2-3(7x-2)-2=0 ?

The solutions to the equation (7x-2)^2-3(7x-2)-2=0 are x=(7+sqrt(17))/(14),x=(7-sqrt(17))/(14)

Find the zeros of (7x-2)^2-3(7x-2)-2=0

The zeros of (7x-2)^2-3(7x-2)-2=0 are x=(7+sqrt(17))/(14),x=(7-sqrt(17))/(14)

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(7 x - 2)^{2} - 3 (7 x - 2) - 2 = 0

x = \frac{7 + 17}{14}, x = \frac{7 - 17}{14}

Solution steps

(7 x - 2)^{2} - 3 (7 x - 2) - 2 = 0

Expand

(7 x - 2)^{2} - 3 (7 x - 2) - 2 : 49 x^{2} - 49 x + 8

49 x^{2} - 49 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 49 ) \pm ( - 49 ) ^{2} - 4 \cdot 49 \cdot 8}{2 \cdot 49}

(- 49)^{2} - 4 \cdot 49 \cdot 8 = 717

x_{1, 2} = \frac{- ( - 49 ) \pm 7 17}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- ( - 49 ) + 7 17}{2 \cdot 49}, x_{2} = \frac{- ( - 49 ) - 7 17}{2 \cdot 49}

x = \frac{- ( - 49 ) + 7 17}{2 \cdot 49} : \frac{7 + 17}{14}

x = \frac{- ( - 49 ) - 7 17}{2 \cdot 49} : \frac{7 - 17}{14}

The solutions to the quadratic equation are:

x = \frac{7 + 17}{14}, x = \frac{7 - 17}{14}

36 x^{2} - 48 x + 16 = 0

\frac{a ^{- 1} + 2}{a ^{- 1} - 2}

\frac{15}{125}

25 (- 8 x^{3} + 3 x^{2} + 6 x)

x^{2} - 6 x = 2

What are the solutions to the equation (7x-2)^2-3(7x-2)-2=0 ?
The solutions to the equation (7x-2)^2-3(7x-2)-2=0 are x=(7+sqrt(17))/(14),x=(7-sqrt(17))/(14)
Find the zeros of (7x-2)^2-3(7x-2)-2=0
The zeros of (7x-2)^2-3(7x-2)-2=0 are x=(7+sqrt(17))/(14),x=(7-sqrt(17))/(14)