What are the solutions to the equation r^2-2r+5=0 ?

The solutions to the equation r^2-2r+5=0 are r=1+2i,r=1-2i

Find the zeros of r^2-2r+5=0

The zeros of r^2-2r+5=0 are r=1+2i,r=1-2i

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r^{2} - 2 r + 5 = 0

r = 1 + 2 i, r = 1 - 2 i

Solution steps

r^{2} - 2 r + 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 5 : 4 i

r_{1, 2} = \frac{- ( - 2 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 2 ) + 4 i}{2 \cdot 1}, r_{2} = \frac{- ( - 2 ) - 4 i}{2 \cdot 1}

r = \frac{- ( - 2 ) + 4 i}{2 \cdot 1} : 1 + 2 i

r = \frac{- ( - 2 ) - 4 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

r = 1 + 2 i, r = 1 - 2 i

∣ 2 - 4 x ∣ = 6

∣ x - 5 ∣ < 7

2 (t + 3) = 4

12 x^{3} - 8 x^{2} - 20 x

1 + 8 x + 9 = - 20 + 2 x

What are the solutions to the equation r^2-2r+5=0 ?
The solutions to the equation r^2-2r+5=0 are r=1+2i,r=1-2i
Find the zeros of r^2-2r+5=0
The zeros of r^2-2r+5=0 are r=1+2i,r=1-2i