What is |x+1|<|x|-x+2 ?

The solution to |x+1|<|x|-x+2 is x<1

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|x+1|<|x|-x+2

∣ x + 1 ∣ < ∣ x ∣ - x + 2

x < 1

Interval Notation

(- \infty, 1)

Solution steps

∣ x + 1 ∣ < ∣ x ∣ - x + 2

Find positive and negative intervals

x < - 1, - 1 \leq x < 0, x \geq 0

Solve the inequality for each interval

x < - 1 or - 1 \leq x < 0 or 0 \leq x < 1

Merge Overlapping Intervals

x < 1

\frac{e ^{4 x}}{e ^{2 x}}

27 r^{6} - 343

\frac{12}{x + 3} \leq 4

x + 1 = 2 x - 1