What is 2sqrt(x+3)<= 8 ?

The solution to 2sqrt(x+3)<= 8 is -3<= x<= 13

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2sqrt(x+3)<= 8

2 x + 3 \leq 8

- 3 \leq x \leq 13

Interval Notation

[- 3, 13]

Solution steps

2 x + 3 \leq 8

Divide both sides by

2

\frac{2 x + 3}{2} \leq \frac{8}{2}

Simplify

x + 3 \leq 4

Square both sides

(x + 3)^{2} \leq 4^{2}

Simplify

x + 3 \leq 16

Move

3

to the right side

x \leq 13

Find singularity points

Find non-negative values for radicals:

x \geq - 3

Combine the intervals

x \leq 13 and x \geq - 3

Merge Overlapping Intervals

- 3 \leq x \leq 13

(\frac{1}{9})^{- 2}

x^{2} + 8 x = 6

∣ y + 3 ∣ \leq 2

- 0.8 a - 8 = 0.2 a