What is (|2x-5|)/(-5)<-1 ?

The solution to (|2x-5|)/(-5) 5

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(|2x-5|)/(-5)<-1

\frac{∣ 2 x - 5 ∣}{- 5} < - 1

x < 0 or x > 5

Interval Notation

(- \infty, 0) \cup (5, \infty)

Solution steps

\frac{∣ 2 x - 5 ∣}{- 5} < - 1

Multiply both sides by

- 1

\frac{∣ 2 x - 5 ∣}{5} > 1

Multiply both sides by

5

∣ 2 x - 5 ∣ > 5

Apply absolute rule: If

∣ u ∣ > a, a > 0

then

u < - a

u > a

2 x - 5 < - 5 or 2 x - 5 > 5

2 x - 5 < - 5 or 2 x - 5 > 5

x < 0 or x > 5

3 + 4 u \geq - 1

\frac{h ^{3}}{h ^{- 6}}

4 h + 1 \geq 9

a^{4} \cdot a^{3}