What are the solutions to the equation (x+6)(x-2)=-7 ?

The solutions to the equation (x+6)(x-2)=-7 are x=1,x=-5

Find the zeros of (x+6)(x-2)=-7

The zeros of (x+6)(x-2)=-7 are x=1,x=-5

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(x + 6) (x - 2) = - 7

x = 1, x = - 5

Solution steps

(x + 6) (x - 2) = - 7

Expand

(x + 6) (x - 2) : x^{2} + 4 x - 12

x^{2} + 4 x - 12 = - 7

Move

7

to the left side

x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 6}{2 \cdot 1}, x_{2} = \frac{- 4 - 6}{2 \cdot 1}

x = \frac{- 4 + 6}{2 \cdot 1} : 1

x = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

98 x - 49 x^{2} - 45

6 a^{2} - 7 ab - 3 b^{2}

4 (y - 3) - 6 y = - 2 (y + 6)

- 3 x^{2} - x + 2

9 (n - 4) - 4 n (n - 4)

What are the solutions to the equation (x+6)(x-2)=-7 ?
The solutions to the equation (x+6)(x-2)=-7 are x=1,x=-5
Find the zeros of (x+6)(x-2)=-7
The zeros of (x+6)(x-2)=-7 are x=1,x=-5